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A 2.7 mW/Channel 48-1000 MHz Direct Sampling Full-Band Cable Receiver
A direct sampling full-band capture (FBC) receiver for cable and digital TV applications is presented. It consists of a 0.18 μm BiCMOS low-noise amplifier (LNA) and a 28 nm CMOS direct RF sampling receiver based on a 2.7 GS/s analog-to-digital converter (ADC) embedded in a system-on-chip (SoC). Digi...
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Published in: | IEEE journal of solid-state circuits 2016-04, Vol.51 (4), p.845-859 |
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Main Authors: | , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , |
Format: | Article |
Language: | English |
Subjects: | |
Citations: | Items that this one cites Items that cite this one |
Online Access: | Get full text |
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Summary: | A direct sampling full-band capture (FBC) receiver for cable and digital TV applications is presented. It consists of a 0.18 μm BiCMOS low-noise amplifier (LNA) and a 28 nm CMOS direct RF sampling receiver based on a 2.7 GS/s analog-to-digital converter (ADC) embedded in a system-on-chip (SoC). Digital signal processing (DSP) plays critical roles to assist analog circuits in providing functionalities and enhancing performances, including digital automatic gain control (AGC), digital phase-locked loop (PLL), and digital ADC compensation. The receiver is capable of receiving 158 256 QAM channels from 48 to 1000 MHz simultaneously, achieving up to 10 Gb/s data throughput for data and video while exceeding Data over cable service interface specification (DOCSIS) and Society of Cable Telecommunications Engineers (SCTE) requirements. The CMOS receiver occupies 1 mm 2 area while consuming 300 mW. The LNA consumes 130 mW and occupies 3 mm 2 area. The total power dissipation from the receiver is 2.7 mW per 6 MHz channel when capturing the entire cable spectrum. |
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ISSN: | 0018-9200 1558-173X |
DOI: | 10.1109/JSSC.2015.2511164 |