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Grothendieck-Lidski theorem for subspaces of Lp-spaces
In 1955, A. Grothendieck has shown that if the linear operator T in a Banach subspace of an L[infin]-space is 2/3-nuclear then the trace of T is well defined and is equal to the sum of all eigenvalues {μk(T)} of T. Lidski, in 1959, proved his famous theorem on the coincidence of the trace of the S1-...
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Published in: | Mathematische Nachrichten 2013-02, Vol.286 (2-3), p.279 |
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Main Authors: | , |
Format: | Article |
Language: | eng ; fre ; ger |
Online Access: | Get full text |
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Summary: | In 1955, A. Grothendieck has shown that if the linear operator T in a Banach subspace of an L[infin]-space is 2/3-nuclear then the trace of T is well defined and is equal to the sum of all eigenvalues {μk(T)} of T. Lidski, in 1959, proved his famous theorem on the coincidence of the trace of the S1-operator in L2(ν) with its spectral trace \documentclass{article}\usepackage{amssymb}\begin{document}\pagestyle{empty}$\sum _{k=1}^\infty \mu _k(T)$\end{document}[Image omitted see PDF]. We show that for p [1, [infin]] and s (0, 1] with 1/s = 1 + |1/2 - 1/p|, and for every s-nuclear operator T in every subspace of any Lp(ν)-space the trace of T is well defined and equals the sum of all eigenvalues of T. Note that for p = 2 one has s = 1, and for p = [infin] one has s = 2/3. [PUBLICATION ABSTRACT] |
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ISSN: | 0025-584X 1522-2616 |
DOI: | 10.1002/mana.201100112 |