Observation of a 1/3 magnetization plateau in PbCuO(SeO)Cl arising from (Cu) clusters of corner-sharing (Cu) tetrahedra

• Published in: Dalton transactions : an international journal of inorganic chemistry 2022-10, Vol.51 (39), p.1517-1521
• Main Authors: Vasiliev, A. N, Berdonosov, P. S, Kozlyakova, E. S, Maximova, O. V, Murtazoev, A. F, Dolgikh, V. A, Lyssenko, K. A, Pchelkina, Z. V, Gorbunov, D. I, Chung, S. H, Koo, H.-J, Whangbo, M.-H
• Format: Article
• ISSN: 1477-9226; 1477-9234
• DOI: 10.1039/d2dt02316d

A mixed-valence compound Pb 2 Cu 10 O 4 (SeO 3 ) 4 Cl 7 has a complex structure consisting of one nonmagnetic Cu + ( S = 0) ion and four nonequivalent magnetic Cu 2+ ( S = 1/2) ions. It exhibits antiferromagnetic ordering at T N = 10.2 K. At a temperature below T N , a sequence of spin-flop transition at B spin-flop = 1.3 T and 1/3 plateau formation at B spin-flip = 4.4 K is observed in the magnetization curve M ( B ). The 1/3 magnetization plateau persists at least up to 53.5 T. The spin exchanges of Pb 2 Cu 10 O 4 (SeO 3 ) 4 Cl 7 evaluated by performing energy-mapping analysis based on DFT+U calculations show that the magnetic properties of Pb 2 Cu 10 O 4 (SeO 3 ) 4 Cl 7 are described by the (Cu 2+ ) 7 cluster of corner-sharing (Cu 2+ ) 4 tetrahedra, and that each (Cu 2+ ) 7 cluster has a S = 3/2 spin arrangement in the ground state. The 1/3 magnetization plateau observed for Pb 2 Cu 10 O 4 (SeO 3 ) 4 Cl 7 is explained by the field-induced flip of every second (Cu 2+ ) 7 cluster within a unit cell. A mixed-valence compound Pb 2 Cu 10 O 4 (SeO 3 ) 4 Cl 7 has a complex structure consisting of one nonmagnetic Cu + ( S = 0) ion and four nonequivalent magnetic Cu 2+ ( S = 1/2) ions.