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Grothendieck-Lidskiǐ theorem for subspaces of Lp-spaces
In 1955, A. Grothendieck has shown that if the linear operator T in a Banach subspace of an L∞‐space is 2/3‐nuclear then the trace of T is well defined and is equal to the sum of all eigenvalues {μk(T)} of T. Lidskiǐ, in 1959, proved his famous theorem on the coincidence of the trace of the S1‐opera...
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Published in: | Mathematische Nachrichten 2013-02, Vol.286 (2-3), p.279-282 |
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Main Authors: | , |
Format: | Article |
Language: | English |
Subjects: | |
Online Access: | Get full text |
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Summary: | In 1955, A. Grothendieck has shown that if the linear operator T in a Banach subspace of an L∞‐space is 2/3‐nuclear then the trace of T is well defined and is equal to the sum of all eigenvalues {μk(T)} of T. Lidskiǐ, in 1959, proved his famous theorem on the coincidence of the trace of the S1‐operator in L2(ν) with its spectral trace \documentclass{article}\usepackage{amssymb}\begin{document}\pagestyle{empty}$\sum _{k=1}^\infty \mu _k(T)$\end{document}. We show that for p ∈ [1, ∞] and s ∈ (0, 1] with 1/s = 1 + |1/2 − 1/p|, and for every s‐nuclear operator T in every subspace of any Lp(ν)‐space the trace of T is well defined and equals the sum of all eigenvalues of T. Note that for p = 2 one has s = 1, and for p = ∞ one has s = 2/3. |
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ISSN: | 0025-584X 1522-2616 |
DOI: | 10.1002/mana.201100112 |