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Large disjoint subgraphs with the same order and size
For a graph G let f ( G ) be the largest integer k such that there are two vertex-disjoint subgraphs of G , each with k vertices, and that induce the same number of edges. Clearly f ( G ) ≤ ⌊ n / 2 ⌋ but this is not always achievable. Our main result is that for any fixed α > 0 , if G has n verti...
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Published in: | European journal of combinatorics 2009-05, Vol.30 (4), p.813-821 |
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Main Authors: | , |
Format: | Article |
Language: | English |
Citations: | Items that this one cites Items that cite this one |
Online Access: | Get full text |
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Summary: | For a graph
G
let
f
(
G
)
be the largest integer
k
such that there are two vertex-disjoint subgraphs of
G
, each with
k
vertices, and that induce the
same number of edges. Clearly
f
(
G
)
≤
⌊
n
/
2
⌋
but this is not always achievable.
Our main result is that for any fixed
α
>
0
, if
G
has
n
vertices and at most
n
2
−
α
edges, then
f
(
G
)
=
n
/
2
−
o
(
n
)
, which is asymptotically optimal. The proof also yields a polynomial time randomized algorithm.
More generally, let
t
be a fixed nonnegative integer and let
H
be a fixed graph. Let
f
H
(
G
,
t
)
be the largest integer
k
such that there are two
k
-vertex subgraphs of
G
having at most
t
vertices in common, that induce the
same number of copies of
H
. We prove that if
H
has
r
vertices then
f
H
(
G
,
t
)
=
Ω
(
n
1
−
(
2
r
−
1
)
/
(
2
r
+
2
t
+
1
)
)
. In particular, there are two subgraphs of the same order
Ω
(
n
1
/
2
+
1
/
(
8
r
−
2
)
)
that induce the same number of copies of
H
and that have no copy of
H
in common. |
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ISSN: | 0195-6698 1095-9971 |
DOI: | 10.1016/j.ejc.2008.09.001 |