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The congruence subgroup problem for low rank free and free metabelian groups
The congruence subgroup problem for a finitely generated group Γ asks whether Aut(Γ)ˆ→Aut(Γˆ) is injective, or more generally, what is its kernel C(Γ)? Here Xˆ denotes the profinite completion of X. In this paper we first give two new short proofs of two known results (for Γ=F2 and Φ2) and a new res...
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Published in: | Journal of algebra 2018-04, Vol.500, p.171-192 |
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Main Authors: | , |
Format: | Article |
Language: | English |
Subjects: | |
Citations: | Items that this one cites Items that cite this one |
Online Access: | Get full text |
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Summary: | The congruence subgroup problem for a finitely generated group Γ asks whether Aut(Γ)ˆ→Aut(Γˆ) is injective, or more generally, what is its kernel C(Γ)? Here Xˆ denotes the profinite completion of X.
In this paper we first give two new short proofs of two known results (for Γ=F2 and Φ2) and a new result for Γ=Φ3:(1)C(F2)={e} when F2 is the free group on two generators.(2)C(Φ2)=Fˆω when Φn is the free metabelian group on n generators, and Fˆω is the free profinite group on ℵ0 generators.(3)C(Φ3) contains Fˆω. Results (2) and (3) should be contrasted with an upcoming result of the first author showing that C(Φn) is abelian for n≥4. |
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ISSN: | 0021-8693 1090-266X |
DOI: | 10.1016/j.jalgebra.2017.01.001 |