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Control of radii of convergence and extension of subanalytic functions
Let g: U\to \mathbb{R} denote a real analytic function on an open subset U of \mathbb{R}^n, and let \Sigma \subset \partial U denote the points where g does not admit a local analytic extension. We show that if g is semialgebraic (respectively, globally subanalytic), then \Sigma is semialgebraic (re...
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Published in: | Proceedings of the American Mathematical Society 2004-04, Vol.132 (4), p.997-1003 |
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Main Author: | |
Format: | Article |
Language: | English |
Subjects: | |
Citations: | Items that this one cites |
Online Access: | Get full text |
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Summary: | Let g: U\to \mathbb{R} denote a real analytic function on an open subset U of \mathbb{R}^n, and let \Sigma \subset \partial U denote the points where g does not admit a local analytic extension. We show that if g is semialgebraic (respectively, globally subanalytic), then \Sigma is semialgebraic (respectively, subanalytic) and g extends to a semialgebraic (respectively, subanalytic) neighbourhood of \overline{U}\backslash\Sigma. (In the general subanalytic case, \Sigma is not necessarily subanalytic.) Our proof depends on controlling the radii of convergence of power series G centred at points b in the image of an analytic mapping \varphi, in terms of the radii of convergence of G\circ\widehat{\varphi}_a at points a\in\varphi^{-1}(b), where \widehat{\varphi}_a denotes the Taylor expansion of \varphi at a. |
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ISSN: | 0002-9939 1088-6826 |
DOI: | 10.1090/S0002-9939-03-07191-0 |