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On the moduli of convexity

It is known that, given a Banach space (X,\|\cdot \|), the modulus of convexity associated to this space \delta _X is a non-negative function, non-decreasing, bounded above by the modulus of convexity of any Hilbert space and satisfies the equation \frac {\delta _X(\varepsilon )}{\varepsilon ^2}\leq...

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Bibliographic Details
Published in:Proceedings of the American Mathematical Society 2007-10, Vol.135 (10), p.3233-3240
Main Authors: Guirao, A. J., Hájek, P.
Format: Article
Language:English
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Summary:It is known that, given a Banach space (X,\|\cdot \|), the modulus of convexity associated to this space \delta _X is a non-negative function, non-decreasing, bounded above by the modulus of convexity of any Hilbert space and satisfies the equation \frac {\delta _X(\varepsilon )}{\varepsilon ^2}\leq 4L\frac {\delta _X(\mu )}{\mu ^2} for every 00 is a constant. We show that, given a function f satisfying these properties then, there exists a Banach space in such a way its modulus of convexity is equivalent to f, in Figiel’s sense. Moreover this Banach space can be taken to be two-dimensional.
ISSN:0002-9939
1088-6826
DOI:10.1090/S0002-9939-07-09030-2