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Solvable Groups with π-Isolators

Let π be any nonempty set of prime numbers. A natural number is a π-number precisely if all of its prime factors are in π. A group G is said to have the π-isolator property if for every subgroup H of G, the set$\root\pi\of H = \{g \in G; g^n \in H,\quad\text{for some}\quad \pi-\text{number}\quad n \...

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Bibliographic Details
Published in:Proceedings of the American Mathematical Society 1984-02, Vol.90 (2), p.173-177
Main Authors: Rhemtulla, A. H., Weiss, A., Yousif, M.
Format: Article
Language:English
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Summary:Let π be any nonempty set of prime numbers. A natural number is a π-number precisely if all of its prime factors are in π. A group G is said to have the π-isolator property if for every subgroup H of G, the set$\root\pi\of H = \{g \in G; g^n \in H,\quad\text{for some}\quad \pi-\text{number}\quad n \}$is a subgroup of G. It is well known that nilpotent groups have the π-isolator property for any nonempty set π of primes. Finitely generated solvable linear groups with finite Prüfer rank, and in particular polycyclic groups, have subgroups of finite index with the π-isolator property if π is the set of all primes. It is shown here that if π is any finite nonempty set of primes and G is a finitely generated solvable group, then G has a subgroup of finite index with the π-isolator property if and only if G is nilpotent-by-finite.
ISSN:0002-9939
1088-6826
DOI:10.2307/2045332