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A FINITE-TO-ONE MAP FROM THE PERMUTATIONS ON A SET
Forster [‘Finite-to-one maps’, J. Symbolic Logic 68 (2003), 1251–1253] showed, in Zermelo–Fraenkel set theory, that if there is a finite-to-one map from ${\mathcal{P}}(A)$ , the set of all subsets of a set $A$ , onto $A$ , then $A$ must be finite. If we assume the axiom of choice (AC), the cardinali...
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Published in: | Bulletin of the Australian Mathematical Society 2017-04, Vol.95 (2), p.177-182 |
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Main Authors: | , |
Format: | Article |
Language: | English |
Subjects: | |
Citations: | Items that this one cites Items that cite this one |
Online Access: | Get full text |
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Summary: | Forster [‘Finite-to-one maps’, J. Symbolic Logic
68 (2003), 1251–1253] showed, in Zermelo–Fraenkel set theory, that if there is a finite-to-one map from
${\mathcal{P}}(A)$
, the set of all subsets of a set
$A$
, onto
$A$
, then
$A$
must be finite. If we assume the axiom of choice (AC), the cardinalities of
${\mathcal{P}}(A)$
and the set
$S(A)$
of permutations on
$A$
are equal for any infinite set
$A$
. In the absence of AC, we cannot make any conclusion about the relationship between the two cardinalities for an arbitrary infinite set. In this paper, we give a condition that makes Forster’s theorem, with
${\mathcal{P}}(A)$
replaced by
$S(A)$
, provable without AC. |
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ISSN: | 0004-9727 1755-1633 |
DOI: | 10.1017/S0004972716000757 |