Loading…
The permutations with n non‐fixed points and the subsets with n elements of a set
We write Sn(a)$\mathcal {S}_n(\mathfrak {a})$ and [a]n$[\mathfrak {a}]^n$ for the cardinalities of the set of permutations with n non‐fixed points and the set of subsets with n elements, respectively, of a set which is of cardinality a$\mathfrak {a}$, where n is a natural number greater than 1. With...
Saved in:
Published in: | Mathematical logic quarterly 2023-08, Vol.69 (3), p.341-346 |
---|---|
Main Authors: | , |
Format: | Article |
Language: | English |
Subjects: | |
Citations: | Items that this one cites |
Online Access: | Get full text |
Tags: |
Add Tag
No Tags, Be the first to tag this record!
|
Summary: | We write Sn(a)$\mathcal {S}_n(\mathfrak {a})$ and [a]n$[\mathfrak {a}]^n$ for the cardinalities of the set of permutations with n non‐fixed points and the set of subsets with n elements, respectively, of a set which is of cardinality a$\mathfrak {a}$, where n is a natural number greater than 1. With the Axiom of Choice, Sn(a)$\mathcal {S}_n(\mathfrak {a})$ and [a]n$[\mathfrak {a}]^n$ are equal for all infinite cardinals a$\mathfrak {a}$. We show, in ZF, that if AC≤n$\mbox{\textsf {AC}}_{\le n}$ is assumed, then [a]n≤Sn(a)≤[a]n+1$[\mathfrak {a}]^n\le \mathcal {S}_n(\mathfrak {a})\le [\mathfrak {a}]^{n+1}$ for any infinite cardinal a$\mathfrak {a}$. Moreover, the assumption AC≤n$\mbox{\textsf {AC}}_{\le n}$ cannot be removed for n>2$n>2$ and the superscript n+1$n+1$ cannot be replaced by n. We also show under AC≤n$\mbox{\textsf {AC}}_{\le n}$ that for any infinite cardinal a$\mathfrak {a}$, Sn(a)≤[a]n$\mathcal {S}_n(\mathfrak {a})\le [\mathfrak {a}]^n$ implies a$\mathfrak {a}$ is Dedekind‐infinite. |
---|---|
ISSN: | 0942-5616 1521-3870 |
DOI: | 10.1002/malq.202300005 |