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Rigorous results for random [formula omitted]-SAT
In recent years there has been significant interest in the study of random k-SAT formulae. For a given set of n Boolean variables, let B k denote the set of all possible disjunctions of k distinct, non-complementary literals from its variables ( k-clauses). A random k-SAT formula F k(n,m) is formed...
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Published in: | Theoretical computer science 2001, Vol.265 (1), p.109-129 |
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Main Authors: | , , , |
Format: | Article |
Language: | English |
Citations: | Items that this one cites Items that cite this one |
Online Access: | Get full text |
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Summary: | In recent years there has been significant interest in the study of random
k-SAT formulae. For a given set of
n Boolean variables, let
B
k
denote the set of all possible disjunctions of
k distinct, non-complementary literals from its variables (
k-clauses). A random
k-SAT formula
F
k(n,m)
is formed by selecting uniformly and independently
m clauses from
B
k
and taking their conjunction. Motivated by insights from statistical mechanics that suggest a possible relationship between the “order” of phase transitions and computational complexity, Monasson and Zecchina (Phys. Rev. E 56(2) (1997) 1357) proposed the random
(2+p)-SAT model: for a given
p∈[0,1], a random
(2+p)-SAT formula,
F
2+p(n,m)
, has
m randomly chosen clauses over
n variables, where
pm clauses are chosen from
B
3
and
(1−p)m from
B
2
. Using the heuristic “replica method” of statistical mechanics, Monasson and Zecchina gave a number of non-rigorous predictions on the behavior of random
(2+p)-SAT formulae. In this paper we give the first
rigorous results for random
(2+p)-SAT, including the following surprising fact: for
p⩽2/5, with probability
1−
o(1)
, a random
(2+p)-SAT formula is satisfiable iff its 2-SAT subformula is satisfiable. That is, for
p⩽2/5, random
(2+p)-SAT behaves like random 2-SAT. |
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ISSN: | 0304-3975 1879-2294 |
DOI: | 10.1016/S0304-3975(01)00154-2 |