Loading…
On the size of maximal antichains and the number of pairwise disjoint maximal chains
Fix integers n and k with n ≥ k ≥ 3 . Duffus and Sands proved that if P is a finite poset and n ≤ | C | ≤ n + ( n − k ) / ( k − 2 ) for every maximal chain in P , then P must contain k pairwise disjoint maximal antichains. They also constructed a family of examples to show that these inequalities ar...
Saved in:
Published in: | Discrete mathematics 2010-11, Vol.310 (21), p.2890-2894 |
---|---|
Main Authors: | , |
Format: | Article |
Language: | English |
Subjects: | |
Citations: | Items that this one cites Items that cite this one |
Online Access: | Get full text |
Tags: |
Add Tag
No Tags, Be the first to tag this record!
|
Summary: | Fix integers
n
and
k
with
n
≥
k
≥
3
. Duffus and Sands proved that if
P
is a finite poset and
n
≤
|
C
|
≤
n
+
(
n
−
k
)
/
(
k
−
2
)
for every maximal chain in
P
, then
P
must contain
k
pairwise disjoint maximal antichains. They also constructed a family of examples to show that these inequalities are tight. These examples are two-dimensional which suggests that the dual statement may also hold. In this paper, we show that this is correct. Specifically, we show that if
P
is a finite poset and
n
≤
|
A
|
≤
n
+
(
n
−
k
)
/
(
k
−
2
)
for every maximal antichain in
P
, then
P
has
k
pairwise disjoint maximal chains. Our argument actually proves a somewhat stronger result, and we are able to show that an analogous result holds for antichains. |
---|---|
ISSN: | 0012-365X 1872-681X |
DOI: | 10.1016/j.disc.2010.06.034 |